2logx-log4-log3+logx
= log (x^2) - log4 + logx
= log( x^3/4)
Make into one log function:
2logx-log4-log3+logx
2 answers
why did I not see that -log3 in there ??
correct answer ....
log ((x^2)(x)/((4)(3))
= log (x^3/12)
correct answer ....
log ((x^2)(x)/((4)(3))
= log (x^3/12)