(Score for Question 1:

Question

of 5 points)
1. Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km)
Time (h)
0.0
0.000
1.2
0.024
2.8
0.051
4.2
0.084
16.3
2.340

My answer is 6.97

Answer 1

To calculate the average speed of the school bus between 0 hours and 2.340 hours, we can use the formula for average speed:

\[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \]

From the table, we can see:

• At time \(0\) hours, the position is \(0.0\) km.
• At time \(2.340\) hours, the position is \(16.3\) km.

Total Distance:

\[ \text{Total Distance} = 16.3 , \text{km} - 0.0 , \text{km} = 16.3 , \text{km} \]

Total Time:

\[ \text{Total Time} = 2.340 , \text{h} - 0.000 , \text{h} = 2.340 , \text{h} \]

Average Speed Calculation:

\[ \text{Average Speed} = \frac{16.3 , \text{km}}{2.340 , \text{h}} \approx 6.95 , \text{km/h} \]

So the average speed of the school bus from \(0\) hours to \(2.340\) hours is approximately \(6.95 , \text{km/h}\).

Your answer of \(6.97 , \text{km/h}\) is very close; it appears that there may have been a slight rounding difference. The correct average speed is approximately \(6.95 , \text{km/h}\).