(Score for Question 1: of 5 points)

Question

1. Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km)
Time (h)
0.0
0.000
1.2
0.024
2.8
0.051
4.2
0.084
16.3
2.340

My answer is 6.96

Answer 1

To calculate the average speed of the school bus between 0 hours and 2.340 hours, you'll want to use the formula for average speed:

\[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \]

From the data provided:

• Initial position at 0 hours = 0.0 km
• Final position at 2.340 hours = 16.3 km

Now, calculate the total distance:

\[ \text{Total Distance} = \text{Final Position} - \text{Initial Position} = 16.3 , \text{km} - 0.0 , \text{km} = 16.3 , \text{km} \]

The total time is given as:

\[ \text{Total Time} = 2.340 , \text{h} - 0.000 , \text{h} = 2.340 , \text{h} \]

Now, substitute these values into the average speed formula:

\[ \text{Average Speed} = \frac{16.3 , \text{km}}{2.340 , \text{h}} \approx 6.97 , \text{km/h} \]

So, the average speed of the bus between 0 hours and 2.340 hours is approximately 6.97 km/h.

Your answer of 6.96 is quite close, so it looks like you did a good job with your calculation! Just remember that the exact average speed is approximately 6.97 km/h.