(Score for Question 1:

Question

of 5 points)
1. Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km)
Time (h)
0.0
工
0.000
1.2
0.024
2.8
0.051
4.2
0.084
16.3
2.340

Answer 1

To find the average speed of the school bus between 0 hours and 2.340 hours, we can use the formula for average speed:

\[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \]

Step 1: Determine Total Distance

From the table, the positions at the two time points are:

• At \( t = 0 , \text{h} \): Position = 0.0 km
• At \( t = 2.340 , \text{h} \): Position = 16.3 km

Total distance traveled: \[ \text{Total Distance} = \text{Position at } 2.340 , \text{h} - \text{Position at } 0 , \text{h} \] \[ \text{Total Distance} = 16.3 , \text{km} - 0.0 , \text{km} = 16.3 , \text{km} \]

Step 2: Determine Total Time

The total time from 0 h to 2.340 h is: \[ \text{Total Time} = 2.340 , \text{h} - 0 , \text{h} = 2.340 , \text{h} \]

Step 3: Calculate Average Speed

Now, we can substitute the values into the average speed formula: \[ \text{Average Speed} = \frac{16.3 , \text{km}}{2.340 , \text{h}} \] Calculating this gives: \[ \text{Average Speed} \approx 6.97 , \text{km/h} \]

Therefore, the average speed of the school bus between 0 h and 2.340 h is approximately 6.97 km/h.