that is the vertex form, not the standard form.
You want
(x-h)^2 = a(y-k)
Rewrite the quadratic function in standard form.
f(x)= x^2 - 8x + 36
I got f(x)= (x-4)^2 + 20
Am I right or wrong?
4 answers
Most authors of Calculus texts classify them as:
1) Standard form: y = ax^2 + bx + c where the a,b, and c are just real numbers.
2) Factored form: y = (ax + c)(bx + d) again the a,b,c, and d are just numbers.
3) Vertex form: y = a(x - b)^2 + c again the a, b, and c are just numbers and (b,c) is the vertex.
1) Standard form: y = ax^2 + bx + c where the a,b, and c are just real numbers.
2) Factored form: y = (ax + c)(bx + d) again the a,b,c, and d are just numbers.
3) Vertex form: y = a(x - b)^2 + c again the a, b, and c are just numbers and (b,c) is the vertex.
Isn't that in Standard form already then?
f(x) = x^2 - 8x + 36
y = ax^2 + bx +c
Or am I missing something?
f(x) = x^2 - 8x + 36
y = ax^2 + bx +c
Or am I missing something?
Take a look how the author of your text or your teacher defines "standard form"
then state the matching equation.
then state the matching equation.
2 answers