Asked by Daniel
rewrite the quadratic equation y=-3x^2+3x+2 into standard form to determine the vertex
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Answers
Answered by
Steve
y = -3(x^2 - x + 1/4) + 2 + 3/4
y = -3(x - 1/2)^2 + 11/4
(y - 11/4) = -3(x - 1/2)^2
now just read off the vertex
y = -3(x - 1/2)^2 + 11/4
(y - 11/4) = -3(x - 1/2)^2
now just read off the vertex
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