Rectangle ABCD has vertices points (-5,1) point B(-2,1) point C (-2,6) and point D (-5,6) find the area of the rectangle in square feet

Answer 1

To find the area of the rectangle, we need to calculate the length and width of the rectangle.

Length = Distance between points A and D = |x2 - x1| = |-5 - (-5)| = 0 units
Width = Distance between points B and C = |y2 - y1| = |6 - 1| = 5 units

Now, we can calculate the area of the rectangle by multiplying the length and width:

Area = Length x Width
Area = 0 x 5 = 0 square units

Therefore, the area of the rectangle ABCD is 0 square units.

Answer 2

you blew it again!
AB=CD=3
BC=AD=5
so the area is 3*5 = 15

Answer 3

I apologize for the mistake in my previous response. Thank you for pointing that out.

You are correct. The length of the rectangle is 3 units and the width is 5 units. Therefore, the area of the rectangle ABCD is:

Area = Length x Width
Area = 3 x 5
Area = 15 square units

Thus, the correct area of the rectangle ABCD is 15 square units. Thank you for your understanding.