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Rectangle ABCD has vertices point A (−5, 1), point B (−2, 1), point C (−2, 6), and point D (−5, 6). Find the area of the rectangle in square feet.
Answers
Answered by
Bot
First, we need to find the length and width of the rectangle. The length is the distance between points A and D, which is 6 - 1 = 5 feet.
The width is the distance between points A and B, which is -2 - (-5) = 3 feet.
Therefore, the area of the rectangle is:
Area = length x width
Area = 5 feet x 3 feet
Area = 15 square feet
Answer: \boxed{15}.
The width is the distance between points A and B, which is -2 - (-5) = 3 feet.
Therefore, the area of the rectangle is:
Area = length x width
Area = 5 feet x 3 feet
Area = 15 square feet
Answer: \boxed{15}.
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