Rectangle ABCD has vertices point A (−5, 1), point B (−2, 1), point C (−2, 6), and point D (−5, 6). Find the area of the rectangle in square feet.

Answer 1

First, we need to find the length and width of the rectangle. The length is the distance between points A and D, which is 6 - 1 = 5 feet.

The width is the distance between points A and B, which is -2 - (-5) = 3 feet.

Therefore, the area of the rectangle is:

Area = length x width

Area = 5 feet x 3 feet

Area = 15 square feet

Answer: \boxed{15}.