Question: The amount of internal energy needed to raise the temperature of .25 kg of water by 0.2 degrees Celsius is 209.3 J. How fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?

Question

KE = (.5)(m)(v^2)
209.3 J = (.5)(.25kg)(v^2)
1674.4 = v^2 **square root both sides**
v = 40.92

^Is ANY of that correct? If not, can anyone help? Thanks so much

Answer 1

I don't see what 1/4 kg of water has to do with a baseball, but you did the problem correctly.

The specific heat of a baseball is different from that of water, and its mass is 1/7 kg, so what you have calculated in NOT the velocity needed to raise the baseball 0.2 degrees. It is an arbitrary number.

Answer 2

yes that is correct

Answer 3

You are right!!

Answer 4

yep! and its 2017. :)

Answer 5

yes and its 2019

Answer 6

Yes, and it’s 2020

Answer 7

Yep and it’s April 20 Year 2069

Answer 8

Correct, and it's 2021

Answer 9

Correct, and it's still 2021

Answer 10

Correct and I'm using this for my final exam tomorrow, thank you Mike !

Answer 11

Yes, and it’s still 2021.

Answer 12

It still holds correct, and its 2022

Answer 13

Yes and it's 2022

Answer 14

yes and its 1997