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The amount of internal energy needed to

raise the temperature of 0.26 kg of water by
0.3�C is 326.5 J.
How fast must a 0.26 kg baseball travel
in order for its kinetic energy to equal this
internal energy?
Answer in units of m/s

1 answer

Require that (1/2)MV^2 = 326.5 J
Then solve for V.

V = 50.1 m/s

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