Asked by mike

Question: The amount of internal energy needed to raise the temperature of .25 kg of water by 0.2 degrees Celsius is 209.3 J. How fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?

KE = (.5)(m)(v^2)
209.3 J = (.5)(.25kg)(v^2)
1674.4 = v^2 **square root both sides**
v = 40.92

^Is ANY of that correct? If not, can anyone help? Thanks so much
Answered by drwls
I don't see what 1/4 kg of water has to do with a baseball, but you did the problem correctly.

The specific heat of a baseball is different from that of water, and its mass is 1/7 kg, so what you have calculated in NOT the velocity needed to raise the baseball 0.2 degrees. It is an arbitrary number.
Answered by Tiffany
yes that is correct
Answered by Jaeda
You are right!!
Answered by Charles
yep! and its 2017. :)
Answered by jasmine
yes and its 2019
Answered by James
Yes, and it’s 2020
Answered by Vanoss
Yep and it’s April 20 Year 2069
Answered by Ian
Correct, and it's 2021
Answered by fella
Correct, and it's still 2021
Answered by Jawad
Correct and I'm using this for my final exam tomorrow, thank you Mike !
Answered by Sara
Yes, and it’s still 2021.
Answered by Diego
It still holds correct, and its 2022
Answered by Yes
Yes and it's 2022
Answered by ,
yes and its 1997
There are no AI answers yet. The ability to request AI answers is coming soon!