Question

Question

Question
A student wants to determine how likely an autosomal dominant trait (X/x) is to be passed on. A father does not have the trait (xx), but the mother does (Xx). What will the Punnett square look like?(1 point)
Responses

50% Xx; 50% xx.
50% Xx; 50% xx.

50% XX; 50% Xx
50% XX; 50% Xx

25% Xx; 75% xx.
25% Xx; 75% xx.

75% Xx; 25% XX

GPT-4o mini · Answer

To set up the Punnett square for the scenario described, we have:

The father's genotype: xx (not having the trait)
The mother's genotype: Xx (having the trait)

When creating a Punnett square, we take the gametes (alleles) from each parent and combine them. The father contributes "x" alleles, while the mother can contribute either "X" or "x" alleles.

The Punnett square would look like this:

      X     x
    ----------
x |   Xx   |   xx   |
    ----------
x |   Xx   |   xx   |

From the Punnett square, we can see the possible genotypes of the offspring:

50% Xx (heterozygous, displaying the trait)
50% xx (homozygous recessive, not displaying the trait)

Therefore, the correct answer from the options provided is:

50% Xx; 50% xx.