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Question

A student wants to determine how likely an autosomal dominant trait (X/x) is to be passed on. A father does not have the trait (xx), but the mother does (Xx). What will the Punnett square look like?(1 point)
Responses

75% Xx; 25% XX
75% Xx; 25% XX

25% Xx; 75% xx.
25% Xx; 75% xx.

50% XX; 50% Xx
50% XX; 50% Xx

50% Xx; 50% xx.

1 answer

To create a Punnett square for this scenario, we need to follow the genotypes of the parents:

  • The father is homozygous recessive (xx).
  • The mother is heterozygous (Xx).

Let's set up the Punnett square:

        X     x
      __________
    x |   Xx  |  xx  |
      |_______|_______|
    x |   Xx  |  xx  |
      |_______|_______|

Now we analyze the outcomes:

  • There are 2 squares showing Xx (heterozygous),
  • There are 2 squares showing xx (homozygous recessive).

This results in:

  • 50% Xx
  • 50% xx

Thus, the correct answer is 50% Xx; 50% xx.