Asked by Yadira
Prove the identit: cosxcotx+sinx=cscx
Answers
Answered by
visoth
1) rewrite cosx (cosx/sinx) + sinx = csc x
2) cosx^2/sinx + sinx = csc x
3) multiply sinx by (sinx/sinx) to get same denominator
this gives you cosx^2/sinx + sinx^2/sinx = cscx
4) combine your fractions
(cosx^2 + sinx^2)/sinx = cscx
5) rewrite numerator
1/sinx= csc x
and there you go it is proven (you have to know your trig identity to do this so look them up if you don't know them)
2) cosx^2/sinx + sinx = csc x
3) multiply sinx by (sinx/sinx) to get same denominator
this gives you cosx^2/sinx + sinx^2/sinx = cscx
4) combine your fractions
(cosx^2 + sinx^2)/sinx = cscx
5) rewrite numerator
1/sinx= csc x
and there you go it is proven (you have to know your trig identity to do this so look them up if you don't know them)
Answered by
Yadira
Thank You! :D
Answered by
visoth
no problem lol this one almost had me stump for alittle
Answered by
Yadira
Ohh it was hard me :/ .Do you think you can answer my other questions?
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