Asked by Angie
Please help..Write the equation for the equilibrium constant (K) of the reaction.
2K2CrO4 + 2HCl --><-- Cr2O7 + H2O + 2KCl
(K2CrO4 is chromate) and (Cr2O7 is dichromate)
2K2CrO4 + 2HCl --><-- Cr2O7 + H2O + 2KCl
(K2CrO4 is chromate) and (Cr2O7 is dichromate)
Answers
Answered by
DrBob222
Your equation isn't balanced. I would write the net ionic equation as
2CrO4^2- + 2H^+ ==> Cr2O7^2- + H2O
Keq = (Cr2O7^2-)/(H^+)^2(CrO4^2-)^2
If you want to keep your equation molecular I would balance it this way.
2K2CrO4 + 2HCl ==> K2Cr2O7 + H2O + 2KCl
2CrO4^2- + 2H^+ ==> Cr2O7^2- + H2O
Keq = (Cr2O7^2-)/(H^+)^2(CrO4^2-)^2
If you want to keep your equation molecular I would balance it this way.
2K2CrO4 + 2HCl ==> K2Cr2O7 + H2O + 2KCl
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