7 moles of ammonia is placed in 14L flask.At equilibrium 0.2M ammonium was found in the flask. What is the equilibrium constant for this reaction. 1.write the balance chemical equation for the above reaction. 2.determine the equilibrium constant for this reaction

Answer 1

1. The balanced chemical equation for the reaction is:

NH3 (g) <=> NH4+ (aq)

2. To determine the equilibrium constant (K) for this reaction, we first need to calculate the initial concentrations of NH3 and NH4+:

Initial concentration of NH3 = (moles of NH3) / (volume of flask)
Initial concentration of NH3 = 7 moles / 14 L
Initial concentration of NH3 = 0.5 M

The equilibrium concentration of NH4+ is given as 0.2 M.

Now, we can write the expression for the equilibrium constant (K) using the concentrations of NH3 and NH4+ at equilibrium:

K = [NH4+] / [NH3]
K = 0.2 / 0.5
K = 0.4

Therefore, the equilibrium constant for this reaction is 0.4.