Question

Bomai places 7 mol of ammonia in 14 L flask.At equilibrium 0.2M ammonium was found in the flask.what is the equilibrium constant kc for this reaction?

Answer 1

The balanced chemical equation for the reaction of ammonia (NH3) forming ammonium ions (NH4+) is:

NH3 (g) ⇌ NH4+ (aq)

At equilibrium, the concentration of NH4+ is given as 0.2 M.

Since 1 mol of NH3 produces 1 mol of NH4+ at equilibrium,

So, the concentration of NH4+ is equal to the concentration of NH3 at equilibrium, which is 0.2 M.

The initial concentration of NH3 is given as 7 mol in a 14 L flask, so the initial concentration of NH3 is:

Initial concentration of NH3 = moles of NH3 / volume of flask
Initial concentration of NH3 = 7 mol / 14 L
Initial concentration of NH3 = 0.5 M

The equilibrium constant (Kc) is equal to the concentration of NH4+ at equilibrium divided by the concentration of NH3 at equilibrium.

Kc = [NH4+] / [NH3]
Kc = 0.2 M / 0.2 M
Kc = 1

Therefore, the equilibrium constant Kc for this reaction is 1.