Question
Bomai places 7 mol of ammonia in the 14 flask.at equilibrium 0.2M ammonium was found in the flask.what is the balanced chemical equation for this reaction?
What is the equilibrium constant kc for this reaction?
What are the conjugate acid and base for this reaction?
What is the equilibrium constant kc for this reaction?
What are the conjugate acid and base for this reaction?
Answers
GPT 3.5
The balanced chemical equation for the reaction is:
NH3 (g) ⇌ NH4+ (aq)
The equilibrium constant (Kc) for this reaction is calculated using the formula:
Kc = [NH4+] / [NH3]
Given that the concentration of NH4+ at equilibrium is 0.2 M, and the original concentration of NH3 was 1 M (7 moles in a 14 L flask), we can calculate Kc as follows:
Kc = 0.2 / 1 = 0.2
Therefore, the equilibrium constant Kc for this reaction is 0.2.
The conjugate acid and base for this reaction are:
Conjugate acid: NH4+
Conjugate base: NH3
NH3 (g) ⇌ NH4+ (aq)
The equilibrium constant (Kc) for this reaction is calculated using the formula:
Kc = [NH4+] / [NH3]
Given that the concentration of NH4+ at equilibrium is 0.2 M, and the original concentration of NH3 was 1 M (7 moles in a 14 L flask), we can calculate Kc as follows:
Kc = 0.2 / 1 = 0.2
Therefore, the equilibrium constant Kc for this reaction is 0.2.
The conjugate acid and base for this reaction are:
Conjugate acid: NH4+
Conjugate base: NH3
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