A to G is 52 degrees below the negative x direction
A to E is 216 - 180 = 36 degrees below negative x direction
so angle AEG = 52 - 36 = 16 degrees
now law of cosines
EG^2 = 200^2 + 160^2 - 2*200*160 cos 16
PLEASE HELP ME!!
The diagram shows the position of three airports . A,E and G. G is 200 kilometers from A, E is 160 kilometers from A, From G the bearing of A is 052 degrees, From A the bearing of E is 216 degrees. How far apart are airports G and E?
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