Please help me, thank you.

Question

A 100 kg astronaut is standing on the outside surface of a 4.50 x 10^4 kg spacecraft. The astronaut jumps away from the spacecraft at 8.00 m/s. What happens to the spacecraft?

Answer 1

multiply (simplified fraction)

-8/3*(7/1)

Answer 2

that's not right can someone please help.

Answer 3

I believe this is a case of conservation of momentums, namely zero since both objects were stationary to start with.
M₁V₁ + M₂V₂ = 0
100*8 + 45000*V₂ = 0
V₂
= -100*8/45000
= -0.0178 m/s.
Answer: The spaceship moves at 0.0178 in the opposite direction as the astronaut.

Answer 4

Erratum:
Answer: The spaceship moves at 0.0178 m/s in the opposite direction as the astronaut.