about one sixth of g on earth (to check)
height = (1/2) G t^2
3.2 = G (1.4)^2
G = 1.63 m/s^2
to check g/6 = 9.81/6 = 1.635
On August 2, 1971, Astronaut David Scott, while standing on the surface of the Moon, dropped a 1.3-kg hammer and a 0.030-kg falcon feather from a height of 1.6 . Both objects hit the Moon’s surface 1.4 after being released. What is the acceleration due to gravity on the surface of the Moon?
1 answer