Please help me solve this: If an object is projected upward with an initial velocity of 112 feet per second from a height h of 128 feet, then its height t seconds after it is projected is defined by the equation h=-16t^2 + 112t + 128. How many seconds after it is projected will it hit the ground?

Answer 1

just solve for t when the height is zero:

-16t^2 + 112t + 128 = 0

just a normal quadratic equation.