The formula h=vt−16t^2 gives the height h, in feet, of an object projected into the air with an initial vertical velocity v, in feet per second, after t

Question

seconds.
If an object is projected upward with an initial velocity of
112 feet per second, at what times will it reach a height of
160 feet above the ground?

Answer 1

160 = 112 t - 16 t^2

solve for t