These problems are worked the same as a stoichiometry problem. That is,
0.5 mol Fe/10s = 0.05 mol/s, then convert to Fe2O3 by
0.05 mols/x x (1 mol Fe2O3)/2 mols Fe) = 0.025 mol Fe2O3/s.
Please help! I don't understand these questions at all. :(
Fe2O3(s) + 2Al(s) -> Al2O3(s) + 2Fe(l)
If 0.50 mol of Fe is produced in 10 secs, what is the rate of consumption of Fe2O3 in mol/s?
A. 5.0 x 10^-2 mol/s
B. 2.5 x 10^-2 mol/s
C. 1.0 x 10^-1mol/s
D. 5.0 mol/s
Thank you!
1 answer
1 answer