Given that:

Question

2Al(s)+(3/2)O2(g)--->Al2O3(s)
change in H(rxn)= -1601 kJ/mol

2Fe(s)+(3/2)O2(g)--->Fe2O3(s)
change in H(rxn)= -821 kJ/mol

Calculate the standard enthalpy change for the following reaction:
2Al(s)+Fe2O3(s)--->2Fe(s)+Al2O3(s)

_______kJ

Answer 1

Use equation 1 as is.
Reverse equation 2 (change the sign) and add to equation 1. Add the delta Hs to arrive at the total delta H for the new reaction.

Answer 2

Thank you so much :)