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Given the balanced equation:

2 Al + Fe2O3 → Al2O3 + 2 Fe

how many grams of Al2O3 will be produced if 68.1 g Al reacts with 112 g Fe2O3?

1 answer

theoretical yield problem. Rather than finding Limiting reagent by getting to moles, lets do one full step becuase we are asked for grams of Al2O3.

68.1 g Al/ molar mass = mol Al times mole ratio times molar mass Al2O3. Same procedure for Fe2O3. Produced less is theoretical yield(you know that was your LR) and that is amount Al2O3 in grams produced.
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