I will do the last one, you do the others the same way
point is (6,-2)
line is y = -3x - 6
slopes of perpendicular lines are negative reciprocals of each other.
So the new line is
y =(1/3)x + b
sub in the given point
-2 = (1/3)(6) + b
-2 = 2 + b
-4 = b
new equation: y = (1/3)x - 4
parallel and perpendicular lines
write the slope-intercept for an equation of the line that passes through the given point and is perpendicular to the graph of each equation (4-2) y=1/2 +1, ( 2,-3) y= -2/3+4 (-8,-7) y=-x-8 (6,-2) y=-3x-6
1 answer
1 answer