the slope must be 3, so using the point-slope form, you have
y-1 = 2(x+2)
y-1 = 2x+4
y = 2x+5
Or, you know that the line must be
y = mx+b
so plug in your point and you have
1 = 2(-2)+b
b = 5
so y = 2x+5
#2 5x+y=9 has slope -1/5
so, the perpendicular line has slope 5
y-1 = 5(x-2)
y-1 = 5x-10
5x-y = 9
Your equation is clearly not right, since plugging in (2,1) gives
2+5*1 = 3
which is false.
1. Write the equation of a line in slope intercept form that is parallel to y = 3x - 2 and passes through the point (-2, 1)
y = -3x-5?
2. Write the equation of the line that passes through (2, 1) and is perpendicular to 5x + y = 9.
x + 5y = 3?
1 answer
1 answer