One molecule of Iodine (I2) and two molecules of sodium chloride (NaCl) combine in a reaction. How many atoms are in the products?

Question

a
2
b
4
c
6
d
3

Answer 1

In the reaction between one molecule of iodine (I₂) and two molecules of sodium chloride (NaCl), we first break down what we have in terms of atoms:

1. One molecule of iodine (I₂) consists of 2 iodine atoms.
2. Two molecules of sodium chloride (NaCl) each consist of 1 sodium atom and 1 chloride atom. Therefore, two molecules of NaCl consist of:
   • 2 sodium atoms (2 Na)
   • 2 chloride atoms (2 Cl)

Now, adding up all the atoms from the reactants, we have:

• From I₂: 2 iodine atoms
• From 2 NaCl: 2 sodium atoms + 2 chloride atoms = 4 atoms

Total atoms = 2 (iodine) + 2 (sodium) + 2 (chloride) = 6 atoms.

Thus, the total number of atoms in the products is 6.

The answer is c) 6.