One molecule of Iodine (I2) and two molecules of sodium chloride (NaCl) combine in a reaction. How many atoms are in the products?

Question

a
2
b
3
c
6
d
4

Answer 1

To determine the number of atoms in the products of the reaction between one molecule of iodine (I₂) and two molecules of sodium chloride (NaCl), we first need to analyze the individual components.

1. One molecule of I₂ contains 2 iodine atoms.
2. Two molecules of NaCl contain:
   • Sodium (Na): 2 sodium atoms (1 from each molecule, and there are 2 molecules)
   • Chlorine (Cl): 2 chlorine atoms (1 from each molecule, and there are 2 molecules)

Now, let's sum up the total number of atoms in the products:

• Iodine atoms from I₂: 2
• Sodium atoms from 2 NaCl: 2
• Chlorine atoms from 2 NaCl: 2

Now we can add them together:

Total atoms = Iodine atoms + Sodium atoms + Chlorine atoms
Total atoms = 2 (I) + 2 (Na) + 2 (Cl) = 6

So, the total number of atoms in the products is 6.

The correct answer is c) 6.