One kind of battery used in watches contains mercur(II) oxide. As current flows, the mercury oxide is reduced to mercury.
HgO(s) + H2O(l) + 2e^- ==> Hg(l) + 2OH^-(aq)
If 2.5x10^-5 amperes flows continuously 1095 days, what mass of Hg(l) is produced?
(2.5x10^-5)(1095days)(24hours/day)(3600seconds/hour) = (mass of Hg)(1 mol Hg/mw Hg)(2 mol e^-/1 mol Hg)
2365.2 = (x grams Hg)(1 mol Hg/200.59gHg)(2 mol e-/1 mol Hg)
= 23.58 grams
1 answer
Check your work. It looks to me as if you have omitted the 96,485 factor. The 2365.2 looks ok.
1 answer