Asked by mercedes
An old battery with an emf of 9.0 V has a terminal voltage of 7.8 V when it is supplying a current of 1.5 mA. What is the internal resistance of the battery?
Answers
Answered by
Henry
r = Vr/I = = (9-7.8)/1.5*10^-3=800 Ohms
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.