Asked by Jematormal91
For the following battery:
Cd(s) | CdCl2(aq) || Cl–(aq) | Cl2(l) | C(s)
Write the reduction half reaction for the C(s) electrode.
Cd(s) | CdCl2(aq) || Cl–(aq) | Cl2(l) | C(s)
Write the reduction half reaction for the C(s) electrode.
Answers
Answered by
DrBob222
Cl2 + 2e ==> 2Cl^-