Asked by Steve
One kind of battery used in watches contains mercury(II) oxide. As current flows, the mercury oxide is reduced to mercury.
HgO(s) + H2O(l) + 2e^- ==> Hg(l) + 2 OH^-(aq)
If 2.5 x 10^-5 amperes flows continuously for 1095 days, what mass of Hg(l) is produced?
HgO(s) + H2O(l) + 2e^- ==> Hg(l) + 2 OH^-(aq)
If 2.5 x 10^-5 amperes flows continuously for 1095 days, what mass of Hg(l) is produced?
Answers
Answered by
DrBob222
How have you approached this problem? You know to calculate coulombs, change to Faraday. etc.
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