The question did not come out as clear as it was typed. It is:
−3a + 4(x^5)b, x ≤ −1
ax − 2b −1, −1 < x < 1
3x^2 − bx + a, x ≥ 1
Not sure how do do this. Please help?
Find all values of a and b so that the function is continuous for all x E R.
f(x)= −3a + 4(x^5)b x ≤ −1
{ ax − 2b −1 < x < 1
3x^2 − bx + a x ≥ 1
2 answers
for f to be continuous, all three definitions must be equal at x=1. Since f is defined at x=1 in three different ways, we need
-3a+4b = a-2b-1
a-2b-1 = 3-b+a
So just solve those for a and b
-3a+4b = a-2b-1
a-2b-1 = 3-b+a
So just solve those for a and b