Mr. Martin springs off a 5 meter high diving board with an upward velocity of 20 m/s.
A. Find Mr. Martin's height, velocity and acceleration after 0.5 seconds.
B. Determine when Mr. Martin will hit the water.
C. What is Mr. Martin's maximum height off the board?
D. What is Mr. Martin's maximum velocity when he hits the water?
E. What is Mr. Martin's velocity when he reaches half of his maximum height?
2 answers
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According to your data, the height would be given by
h =-4.9t^2 + 20t + 5
totally absurd numbers, as you will see when we "solve" this problem
we have a downwards parabola and the t of the vertex is -20/-9.8
= appr 2.04 seconds
his maximum height is -4.9(2.04)^2 + 20(2.01) + 5
= 25.4 m , wow!! , looks like Superman has taken up diving.
When Clark hits the water, h = 0
-4.9t^2 + 20t + 5 = 0
Use the quadratic formula, reject the negative, and realize that he must have been in the air for over 4 seconds.
Did somebody just randomly make up these numbers? Surely no textbook would have that question, or does it??
h =-4.9t^2 + 20t + 5
totally absurd numbers, as you will see when we "solve" this problem
we have a downwards parabola and the t of the vertex is -20/-9.8
= appr 2.04 seconds
his maximum height is -4.9(2.04)^2 + 20(2.01) + 5
= 25.4 m , wow!! , looks like Superman has taken up diving.
When Clark hits the water, h = 0
-4.9t^2 + 20t + 5 = 0
Use the quadratic formula, reject the negative, and realize that he must have been in the air for over 4 seconds.
Did somebody just randomly make up these numbers? Surely no textbook would have that question, or does it??
2 answers