Let the cost of a 2-inch marble be \( x \) dollars. Then, since the 1-inch marbles cost 30 cents less than the 2-inch marbles, the cost of a 1-inch marble would be \( x - 0.30 \) dollars.
Rochelle buys 25 one-inch marbles for a total of $10:
\[ 25(x - 0.30) = 10 \]
Now we can solve for \( x \):
- Distribute the 25:
\[ 25x - 7.50 = 10 \]
- Add 7.50 to both sides:
\[ 25x = 17.50 \]
- Divide by 25:
\[ x = \frac{17.50}{25} = 0.70 \]
Thus, the cost of a 2-inch marble is \( \boxed{0.70} \).
So the answer is C. 0.70.