e^- (k oo) -----> zero
no matter how big k is (short of oo :)
Let g(t) be the Glucose concentration in blood stream of a person at time t.
g(t) = 1/k(R - (R - k*go)e^(-kt/v))
Where go - initial glucose concentration (at t=0),
v - volume of blood in Humana body ,
R - rate at which glucose is introduced into blood stream and
k is he fraction of glucose removed from blood stream
Find an expression for glucose concentration in blood stream of a person after a long time.
So here when t tends to infinity the terms inside the second bracket is divided by a very large value and does they tends to zero or is there any effect of k , even t tends to infinity?
2 answers
That means g(t) tends to 1/k(R) right?