Landing with a speed of 87.7 m/s, and traveling due south, a jet comes to rest in 939 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.

Question

Magnitude of acceleration

Answer 1

a=(v²-vₒ²)/2s=(-vₒ²)/2s=
= - 87.7²/2•939= - 4.1 m/s².
v is directed to the south,
a is directed to the north.