initial velocity = 78.3 m/s
final velocity = 0 m/s
distance traveled - 959 m
a = ?
use
(final velocity)^2 = (initial velocity)^2 + 2ad
solve equation for 'a'.
Landing with a speed of 78.3 m/s, and traveling due south, a jet comes to rest in 959 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.
4 answers
3.2
3.2 m/s^2
omg