Landing with a speed of 78.3 m/s, and traveling due south, a jet comes to rest in 959 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.

Answer 1

a=[v²(fin)-v²(init)]/2•s= - 78.3²/2•959 = = -3.2 m/s².
"a "is opposite to the velocity, i.e., to the north.