For 4, if they're independent, it would look something like this right?
E= { SFF, SFS, SSF, FFS, FSS, FSF, FFF}
1 s 2s 2s 1s 2s 1s 0s
With s standing for success and the numbers being the number of successes.
Justify whether or not the following is a binomial.
Rolling a fair die 3 times and observing the number of times a 6 is thrown.
I know that the binomial rules are :
1. The number of trials in the experiment is fixed.
2. There are two outcomes of each trial: "success" and "failure".
3. The probability of success in each trial is the same.
4. The trials are independent of each other.
1. Fixed - are 3 trials.
2. There is a success if it lands on 6 and failure if it lands on any number that is not 6.
success/p =1/6 fail/q=5/6
3. 1/6+5/6=1
4. I don't know how to put together the words to explain this.
2 answers
(1/6)(1/6)(1/6) = 1/216
Independent means that the outcome of the first trial does not impact the second trial.
In this case good. yes independent
BUT if you had 6 cards numbered 1 to 6
and you drew the first and had the number 3
the chance was 1/6 of getting three.
HOWEVER if you do NOT put that BACK, the chance of getting three will be zero on the next draw and the chance of getting the number 2 will be 1/FIVE. Second draw therefore DEPENDENT on first draw..
Independent means that the outcome of the first trial does not impact the second trial.
In this case good. yes independent
BUT if you had 6 cards numbered 1 to 6
and you drew the first and had the number 3
the chance was 1/6 of getting three.
HOWEVER if you do NOT put that BACK, the chance of getting three will be zero on the next draw and the chance of getting the number 2 will be 1/FIVE. Second draw therefore DEPENDENT on first draw..