Answers by visitors named: lijm

But wouldn't the highest price be 200 when x=0? since when x is 2 and so on the price seems to decrease.
Wait. I think it is 8000. I set them equal to each other and then divided 48000 by 6. At first, I was confused because I thought I was just repeating the profit function.
continued because I accidentally hit submit 3x=-2x+5 3x+2x=-2x+5+2x 5x=5 x=1
Is my answer correct? Do I need to add anything?
I used the elimination method and got 0=0. Does that mean zero number of solutions?
Since the ball is less than the bat, would it be subtracted?
Do I divide 9 by 12 (12 months in a year) and use that as t?
t=3/4?
Oops not I= Prt I meant A=P(1+rt)
How do I set it up for the annual rate?
What I know: P=35,R=5.1%,T=7 (but 7 years ago) m I assume is 1 A= 35(1+0.051/1) ^1*-7
She sold 50 deluxe bouquets and 70 special bouquets.
Am I supposed to know how many gold medalists were in the 2014 winter Olympic games? Like when they ask for set builder notation for vowels, I get it is {a,e,i,o,u} A = {x l x is a vowel}
Or I just write it like A= {x l x is the number of gold medalists in the 2014 Winter Olympic games).
My second and last question: For { x l x is a digit in the number 351,646}, the roster would be written as {2,3,4,5,6} right?
For example, the sets: A={2,4,6,8} B= {6,7,8,9,10} when a question asks for the elements in B and the answer is n (B)=3 (that is the answer that my professor gave me) can I think of it as the numbers that are only found in set B? (7,9,10) In set A and set B, the numbers 6 and 8 are both present.
As in X = {13,4,5,6} and Y = {2,11,24,7} They have no elements/numbers in common so X∩Y = { }.
For a , I know that it is 106. n(A U B) = 80+68-42=106
But I am stuck on part b. Would it be : n(A U Bcomplement) = n(a) - n(A ∩ B) and n (Acomplement U B) = n(b) - n(A ∩ B). Or does DeMorgan's law apply to sets with complements?
Would it apply in the sense of n(AUBcomplement) = n(AcomplementUB)?
I am only familiar with the grade school method of probability.
I should clarify that I did 3x3x5x4^3.
Oh! That makes sense now!
And for c(8,6), I did 8!/(8-6!) =8!/2! = 8*7*6*5*4*3*2*1/2*1 =40320/2=20160 but I think it is wrong.
Leaving C(11,2)=55 c) This part is stumping me. Would it be 7 men - 5 women=2 remaining? I don't know how to continue.
Separate as in if you were to draw a venn diagram,the circle for e would not connect with the circle for f.
Oh wait... they talking about complement c. Nevermind.
This was in reference to E= {2,4,6} and F={1,3,5}. The question asked if events E and F are complementary.
To be more clear with the table, the 1-2 belongs to 650, 3-4 to 200, and 5 or more to 150.
Sorry, I meant doesn't P (F l E) have to be equal to P (F)? Or vice versa ( P(E l F) be equal to P(E)?
Oops i meant -5 for the table value.
I attempted to find the E(X) and got .61 (1/5000)*(2000)+(1/5000)*(500)+(3/5000)*(100)+(10/5000)*(25).
And then the standard deviation is the square root of the variance?
a) then just the birthrates? b) 13.7/1000, 13.8/1000 instead?
For 4, if they're independent, it would look something like this right? E= { SFF, SFS, SSF, FFS, FSS, FSF, FFF} 1 s 2s 2s 1s 2s 1s 0s With s standing for success and the numbers being the number of successes.
If it doesn't meet every single rule, then it is not a binomial?
Nevermind I actually plugged in the wrong number for x. Please ignore.
For the second table: Frequencies: 3.4 appears once, 3.5 appears once, 3.2 appears once, 3.7 appears once, 3.9 appears once, 3.8 appears once. 6 total items. X 3.4 3.5 3.2 3.7 3.9 3.8 p(x=x) 1/6 1/6 1/6 1/6 1/6 (3.4) * (1/6) + (3.5) * (1/6)+(3.2) * (1/6) + (3.7) * (1/6)+ (3.9) * (1/6) + (3.8) * (1/6) = 3.6 = mean standard deviation = (3.4)*(1/6-3.6)^2+(3.5)*(1/6-3.5)^2+(3.2)*(1/6-3.6)^2+(3.7)*(1/6-3.6)^2+(3.9)*(1/6-3.6)^2+(3.8)*(1/6-3.6) square the answer and i think it might be 16 but please correct me if i'm wrong.
For part c, it looks like the mean is larger for NY so I think NY has more court cases than Pennsylvania.
I must find P(B) right? I designated B for cheese and A for meat.
I was wondering because my professor gave us these answers: a) 30/128 b) 6/128 c) 70/128 d) 78/128 e) 25/40 f)12/25
Thats what the calculator gave me and the question was actually written like that. It was on a review sheet.
But are 3 and 4 set up right? That's all I'll ask and I'll shut up.
I think I used the wrong formula for 3.
x/corn= 300 and y/soybeans=200
x+y=500 ---> y=500-x 42x+30(500-x)=18,600 42x+15000-30x=18,600 12x+15000-15000=18600-15000 12x=3600 x=300 300+y=500 300-300+y=500-300 y=200
Or 1- p(t)*p(p)?