Has your teacher talked about sulfur occurring naturally as S8?
That would change what you have done. If s/he hasn't talked about that, you still don't have mols Al2S3 correct. Based on your equation I think 1 mol S x (1 mol Al2S3/3 mol S) = 0.333 mol Al2S3 is the correct answer. Grams of Al2S3 are correct based on your answer of 0.166 mol Al2S3.so your method must be ok for that part of the problem.
Just checking an answer...
I was given Aluminum + Sulfur yields.. & I was to finish & balance & answer the questions.
2Al + 3S => Al2S3
If 1 mole of sulur reacts, how many moles of aluminum sulife are produced?
.166 mol Al2S3
How many grams of aluminum sulfide is this?
24.9 g
1 answer
1 answer