Aluminum reacts with sulfur gas to form aluminum sulfide. Initially 1.18 ml of aluminum and 2.25mol of sulfur are combined.

1. write a balanced equation?
2. what is the limiting reaction?
3. what is the theoretical yield of aluminum sulfide in moles?
How many moles of excess reactant remain unreacted?

I will take any help I can on this one please?

1 answer

ml of aluminum? Hmmmm. So get the denstiy of aluminum, and convert the ml to mg. This is odd, check your problem.
Now convert the mass of Al to moles.

2Al+ 3S>>>Al2S3

Notice for each mole of S, you need 2/3 mole of Al. If you do not have that much of Al, then Al is the limiting reageant.