Joe has a collection of nickels and dimes that is worth $6.05 if the number of dimes was double and the number of nickels was decreased by 10 the value of the coins would be $9.85 how many nickels and dimes does he have?

Answer 1

case 1:
let the number of nickels be n
let the number of dimes be d
5n + 10d = 605
n + 2d = 121

case 2
number of nickels ---> n - 10
number of dimes ---> 2d
5(n-10) + 10(2d) = 985
5n - 50 + 20d = 985
5n + 20d = 1035
n + 4d = 207

subtract them
2d = 86
d = 43 then n = 35

He has 43 dimes and 35 nickels

Answer 2

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