Question
A collection of nickels dimes and quarters consists of 50 coins with a total of $5.50. If there are two times as many dimes as quarters find the number of each type of coins?
Answers
Reiny
quarters --- x
dimes ----- 2x
nickels --- 50 - 3x
equation based on "value" of those coins:
25x + 10(2x) + 5(50-3x) = 550
25x + 20x + 250 - 15x = 550
30x = 300
x=10
there are 10 quarters, 20 dimes and 20 nickels
dimes ----- 2x
nickels --- 50 - 3x
equation based on "value" of those coins:
25x + 10(2x) + 5(50-3x) = 550
25x + 20x + 250 - 15x = 550
30x = 300
x=10
there are 10 quarters, 20 dimes and 20 nickels
Henry
post it.