Asked by Lea'

A box contains $7.80 in nickels, dimes, and quarters. There are 46 coins in all, and the sum of the numbers of nickels and dimes is 2 less than the number of quarters. How many coins of each kind are there?
Answered by Steve
5n+10d+25q = 780
n+d+q = 46
n+d = q-2

Now just solve.
Answered by dfgdf
56456
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