Asked by dawn

a jar contains $8.75 in nickels, dimes and quarters. There are two times as many dimes as there are nickels, and 10 more dimes than quarters, how many of each coin are in the jar?
Answered by PsyDAG
Let x = number of dimes, then x/2 for nickels and
x-10 for quarters.

5x/2 + 10x + 25(x-10) = 875

Solve for x, then x/2 and x-10.
Answered by Anonymous
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