Ask a New Question
Search
It takes 2.5 J of energy to stretch a helical spring by 15 cm. Determine the spring
constant.
1 answer
PE=kx²/2
k=2•PE/ x²=
=2•2.5/0.15²=222 N/m
Ask a New Question
or
answer this question
.
Similar Questions
It takes 7.9 J of work to stretch a spring 4.6 cm from its unstressed length. How much (in J) spring potential energy is then
0 answers
It takes 6.7 J of work to stretch a spring 4.4 cm from its unstressed (relaxed) length.
How much work (in J) is needed to
2 answers
It takes 5.28 J of work to stretch a Hookes Laq spring 9.82 cm from its unstressed length. How much extra work is required to
0 answers
If it takes 4.00 J of work to stretch a Hooke's Law spring 10.0 cm from its unstressed length, determine the extra work required
3 answers
more similar questions